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.1x^2+2.4x+1.44=405
We move all terms to the left:
.1x^2+2.4x+1.44-(405)=0
We add all the numbers together, and all the variables
.1x^2+2.4x-403.56=0
a = .1; b = 2.4; c = -403.56;
Δ = b2-4ac
Δ = 2.42-4·.1·(-403.56)
Δ = 167.184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{167.184}}{2*.1}=\frac{-2.4-\sqrt{167.184}}{0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{167.184}}{2*.1}=\frac{-2.4+\sqrt{167.184}}{0.2} $
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